If the coefficient of kinetic friction between tires and dry pavement is 0.800, what is the shortest distance in which an automobile can be stopped by locking the brakes when traveling at 29.4 m/s ?

The shortest distance in which an automobile can be stopped by locking the brakes when traveling at 29.4 m/s = 55.125 m = 55.13 m

Explanation:

Coefficient of kinetic friction = 0.8

Frictional force can be evaluated using μN

where N is the normal reaction = mg

Fr = 0.8 m × 9.8 = 7.84 m

The car stops with th help of friction, this friction manifests in a form of decelerating force.

This frictional force will be equal to the ma force,

ma = 7.84 m

a = 7.84 m/s²

But Since it's deceleration, this acceleration is - 7.84 m/s²

So, using the equations of motion,

u = initial velocity = 29.4 m/s

v = final velocity = 0 m/s (since it comes to a stop finally)

x = distance travelled before stopping

a = - 7.84 m/s²

v² = u² + 2ax

0² = 29.4² + 2(-7.84)(x)

15.68 x = 864.36

x = 55.125 m = 55.13 m

d. platinum would have the greatest temperature increase because it has the lowest specific heat.

the aurora is formed when charged particles emitted from the sun during a solar flare penetrate the earth's magnetic shield and collide with atoms and molecules in our atmosphere. these collisions result in countless little bursts of light, called photons, which make up the aurora.

auroras are generated by charged solar particles hitting molecules in earth's atmosphere. this usually happens in high latitudes, because our planet’s magnetic field tends to funnel these particles toward the poles. that’s why it can be experienced in northern ohio.