How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 4.00 cm2?

Explanation:

Let us assume that the separation of plate be equal to d and the area of plates is . As the capacitance of capacitor is given as follows.

            C =

It is known that the dielectric strength of air is as follows.

               E =

Expression for maximum potential difference is that the capacitor can with stand is as follows.

                       dV = E × d

And, maximum charge that can be placed on the capacitor is as follows.

               Q = CV

                   =

                   =

                   =

                   =

or,                = 10.62 nC

Thus, we can conclude that charge on capacitor is 10.62 nC.

would be false hope this out

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.