A plane flying horizontally at a speed of 50 m/s and at an elevation of 160 m drops a package, and 2.0 s later it drops a second package. How far apart will the two packages land on the ground if air resistance is negligible?

386 m

Explanation:

Let's call the horizontal distance between the point of launch and the point of landing of the first package .

2 seconds after landing at , the plane has travelled a horizontal distance of .

At this new point, the second package is launched. Because it is launched under the same conditions as the first, its horizontal distance from its point of launch is also .

To determine , we determine the time of fall of the package. Being a vertical motion, the drop has an initial velocity, , of 0 m/s with acceleration, , and a distance, , of 160 m. We use the equation of motion:

In this time, the package, with a horizontal velocity of 50 m/s, travels the horizontal distance, , of

The distance apart between both packages is

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation: