A system undergoing a power cycle develops a steady power output of 0.3 kW while receiving energy input by heat transfer at a rate of 2400 Btu/h. Determine the thermal efficiency and the total amount of energy developed by work, kW · h, for 1 full year of operation.

The thermal efficiency is 43%.

The total amount of energy developed by work is 397 kW in one year.

Explanation:

Given that,

Power output = 0.3 kW

Heat energy = 2400 Btu/h = 0.703 kW

We need to calculate the thermal efficiency

Using formula of efficiency

Put the value into the formula

The thermal efficiency is 43%.

(b). We need to calculate the total amount of energy

Using formula of energy

Hence, The thermal efficiency is 43%.

The total amount of energy developed by work is 397 kW in one year.

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

higher potential

explanation:

because it is in a high speed so it must move into a of high potential