A parallel-plate capacitor consists of two square plates 13 cm on a side, spaced 0.40 mm apart with only air between them. What is the maximum energy that can be stored by the capacitor?

Explanation:

Given data :

Area of the plate = 0.13×0.13

                             = × m²

Distance between the plates = 0.40 mm = 400× m

The critical strength of the field in case of air is 3.0 MV/m.

Lets find the voltage in case of air as a dielectric.

V = 3××400×

V = 1200 V

Now we find capacitance,

C = εA/d

C = (8.854×)(16.9×)/(400×)

  = 374× F = 374pF

Let's find energy,

E = (1/2)(374×)(1200)²

E = 269.28 × J

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