When you push a 1.70 kg book resting on a tabletop it takes 2.60 N to start the book sliding. Once it is sliding, however, it takes only 1.50 N to keep the book moving with constant speed. What are the coefficients of static and kinetic friction between the book and the tabletop

Coefficient of static friction  ,μs = 0.15

Coefficient of kinetic friction  ,μk = 0.089

Explanation:

Given that

m = 1.7 kg

Static friction :

The force required to start the motion F= 2.6 N

We know that when book is in rest condition then static friction force act on it.

We know that the maximum value of the static friction force

fr = μ m g

At limiting condition

F= fr

2.6 =  μ m g

2.6 =  μ x 1.7 x 9.81

μ = 0.15

Kinetic friction :

F= 1.5 N

When the book is in moving condition then kinetic friction force act on it.

We know that the maximum value of the kinetic friction force

fr = μ m g

F= fr

=  μ m g

1.5 =  μ x 1.7 x 9.81

μ = 0.089

Coefficient of static friction  ,μs = 0.15

Coefficient of kinetic friction  ,μk = 0.089

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explanation:

it is the second option.