Jack starts walking east ( x-direction) at a pace of 2 m/s. Jill, who is very upset with Jack, is running west (- x-direction) towards him at a rate of 4 m/s and is initially 200 meters to the east of Jack when she sees him. When and where does she run into him?

Jill will ran into jack after 33.33 sec.

The distance traveled by Jack in 33.33 seconds is 66.67 m.

Explanation:

Given that,

Speed in x direction= 2 m/s

Distance = 200 m

Rate = 4 m/s

Let after t seconds, she will run into him.

Therefore,  total displacement of Jill after t seconds = 4t meters

and total displacement of Jack after t seconds = 2t meters

Initially they were separated by a distance 200 meters

We need to calculate the time,

Using formula of total distance

Jill will ran into jack after 33.33 sec.

We need to calculate the distance traveled by Jack in 33.33 seconds

Using formula of distance

Put the value into the formula

Hence, Jill will ran into jack after 33.33 sec.

The distance traveled by Jack in 33.33 seconds is 66.67 m.