A resistor is connected in series with a power supply of 23.90 V. The current measure is 0.60 A. What is the resistance (in Ω) of the resistor?

The resistance in this circuit is 39.8 ohms.

Explanation:

Any circuit having resistor, battery and ammeter connected in series will obey the ohm's law in basic case. So according to the Ohm's law, the current flowing in the circuit through the ammeter will be equal to the voltage shown in the voltmeter or battery and resistor is the proportionality constant. So with this law

V = IR

So, Resistance R = V/I

As the voltage is given as 23.90 V and the current is given as 0.6 A, then resistance is

R = 23.90/0.6 = 39.8 ohms.

So, the resistance in this circuit is 39.8 ohms.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.