What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is 1.75 m wide and 9.00 m below the top of the cliff?

1.292 m/s

Explanation:

For her trajectory motion, the time taken to descend to a height of 9 m is given as

t = √(2H/g) = √[(2×9)/9.8] = 1.355 s

Then the range (horizontal distance covered) is related to the time to reach that height and the corresponding horizontal velocity as shown in

R = ut

where u = initial horizontal velocity

1.75 = u × 1.355

u = 1.292 m/s

This is the minimum speed just as she leaves the top of the cliff to miss the ledge described in the question.

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )

resonant frequency