You stand 17.5 m from a wall holding a softball. You throw the softball at the wall at an angle of 30.5 ∘ from the ground with an initial speed of 20.5 m / s. At what height above its initial position does the softball hit the wall? Ignore any effects of air resistance.

5.39 m

Explanation:

From kinematics

where t is time, s is distance and is initial speed in x direction

Now 17.5=17.6634 t

=0.99 s

Using the equation of kinematics

h=5.39 m

as a general rule, scissors have blades less than 6 in (15 cm) long and usually have handles with finger holes of the same size. shears have blades scissors used to cut hair or fabric must be much sharper.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards