Physics, 24.02.2020 19:05 lily2998

A bug is on the rim of a 78 rev/min, 12 in. diameter record. The record moves from rest to its final angular speed in 2.91 s. Find the bug’s centripetal acceleration 1.5 s after the bug starts from rest. (1 in = 2.54 cm). Answer in units of m/s 2 .

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Answer from: yuoy

Centripetal Acceleration = 2.701 m/s²

Explanation:

Given:

Starting from rest so initial angular velocity ωi = 0 rad/s

Final angular velocity ωf= 78 rev/min =78 × 2π /60 rad/s = 8.168 rad/s

Radius of Rim =d/2 =12/6= 6 in = 6× 2.54 cm =15.24 cm = 0.1524 m

angular acceleration α = (ωf - ωi)/t = (8.168 rad/s - 0 rad/s)/2.91 s

α =2.807 rad/s²

now to find angular velocity at 1.5 s we have

ω = α × t = 2.807 rad/s² × 1.5 s = 4.210 rad/s

so centripetal acceleration ac = ω² r = (4.210 rad/s)² × 0.1524 m

ac= 2.701 m/s²

Answer from: Quest

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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A bug is on the rim of a 78 rev/min, 12 in. diameter record. The record moves from rest to its final...

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