7. For a constant force, suppose the duration of
impact on an object is doubled.
a. How much is the impulse increased?
b. How much is the resulting change in
momentum increased? (7.2)

a. impulse increases by the square of the force.

b. momentum also increases

Explanation:

As we know, force is defined as the product of mass and acceleration of the object. Impulse is nothing but the impulse of an object moving is defined as the integral of all the forces acting on the object. As we know that force is a vector quantity and hence the impulse. Since impulse is the integral of all the forces. Here, in the question, it is given that the force is doubled then if you integrate then you get a square function. So, the impulse increases by square function.

Iwould think it is temperature, silica, oxides (gases)

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.