The power that a resistor must dissipate is jointly proportional to the square of the current flowing through the resistor and the resistance of the resistor. If a resistor needs to dissipate 63 watts of power when 3 amperes of current is flowing through the resistor whose resistance is 7 ohms comma find the power that a resistor needs to dissipate when 9 amperes of current are flowing through a resistor whose resistance is 5 ohms.

405 watt

Explanation:

Since the power is I^2 *R

I = current = 9 ampere

R = resistance =5 ohms

P = 9^2 * 5 = 405 watts

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft