Particle moves in a circle of radius 2.0 m with anglular acceleration0.010 radians/s2. The particle starts from rest. At what time is the particleback at its starting position? Pick the closest answer.

D. 35 s.

Explanation:

Given:

r = 2 m

ωi = 0 rad/s

α = 0.01 rad/s^2

θ = 360°

= 2pi.

Therefore,

θ = 2pi

= 6.284 m

Using equation of motion,

θ = ωit + 1/2 × αt^2

6.284 = 1/2 × 0.01t^2

= sqrt(1256.64)

t = 35.45 s.

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