How many seconds does it take to reach 18 m/s starting from rest if the train’s mass, including its load, is 5.15 × 104 kg , assuming 95.0% efficiency and constant power?

a) Power consumption rate = 409.5 KW

b) Time taken to reach 18 m/s = 42.86 s

Explanation:

a) Power is given by P = IV

where I = current drawn = 630 A

V = voltage = 650 V

P = 630 × 650 = 409500 W = 409.5 KW

b) Power is also given as P = Force × velocity

Force = ?

v = 18 m/s

Power = 95% of 409500 = 389025 W (95% efficiency)

Force = Power/velocity = 389025/18 = 21612.5 N

Force = mass × acceleration = 5.15 × 10⁴ × a

51500a = 21612.5

a = 21612.5/51500 = 0.42 m/s²

u = initial velocity = 0 m/s

v = final velocity = 18 m/s

a = 0.42 m/s²

t = ?

v = u + at

18 = 0 + 0.42t

t = 18/0.42 = 42.86 s

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

gas and liquid