A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii and are of uniform density. If the three are released simultaneously at the top of an inclined plane and roll without slipping, which one will reach the bottom first?

Solid sphere will reach the bottom first.

Explanation:

It does not matter having equal masses and radii and uniform density. It's about the shape of object, their rotational inertia and how much the mass is more concentrated towards the center. As we know that the sphere's mass is more towards the center in comparison with hollow pipe and cylinder. As in hollow pipe the mass is towards the edges not towards the center. The moment of inertia for solid sphere is given as follows.

Moment of inertia for sphere = 2/5MR²

Its value is less then those of hollow pipe and cylinder so it will win the race and will reach the bottom first.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

true is the correct answer

hope i