At t1 = 1.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is At t2 = 2.00 s (less than one period later), the acceleration is The period is more than 1.00 s. What is the radius of the circle?

meters

Explanation:

See the remaining part of required information in the attached image

Solution

The formula for calculating velocity is equal to

Where v is the velocity, are time range for two acceleration vectors and angle between two acceleration vector respectively and r is the radius of the circle

Putting the give values in above equation we get

Acceleration is equal to

Radius is equal to

Putting the given values we get -

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.