A 11.0 µF capacitor is charged to 100 V and is then connected across a 470 Ω resistor only. What is the voltage accross the capacitor after 8.00 ms?

The voltage across the capacitor after 8.00 ms is 35.375 V.

Explanation:

Given that,

Capacitor = 11.0 μF

Voltage = 100 V

Resistance = 470 Ω

Time = 8.00 ms

We need to calculate the current

Using formula of current

Put the value into the formula

We need to calculate the voltage

Using ohm's law

We need to calculate the voltage across the capacitor after 8.00 ms

Using formula of voltage

Hence, The voltage across the capacitor after 8.00 ms is 35.375 V.

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