What would be the speed of the boxes when box b has fallen a distance of 0.50 m? The coefficient of kinetic friction between box a and the surface it slides on is 0.20. Use conservation of energy.

The given question is incomplete. The complete question is as follows.

Boxes A and B in the figure have masses of 13.4 kg. and 4.8 kg. , respectively. The two boxes are released from rest. What would be the speed of the boxes when box b has fallen a distance of 0.50 m? The coefficient of kinetic friction between box a and the surface it slides on is 0.20. Use conservation of energy.

Explanation:

Let us assume that box B is falling down, so equation of force for box B is as follows.

             T = .......... (1)

Now, force of equation for box A is as follows.

            T = ........... (2)

We will equate both equation (1) and (2) as follows.

        =

      a =

         = 1.1415

Now, we will calculate the velocity of the box after falling through a distance of 0.50 m as follows.

                    =

                    = 1.07 m/s

Thus, we can conclude that speed of the given boxes is 1.07 m/s.

terd muffin is the correct answer

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is