A force of F = 125 N is used to drag a crate 3.0 m across a floor. The force is directed at an angle upward from the crate so the vertical part of the force is Fv = 65 N and the horizontal part of the force is Fh = 107 N. How much work is done on the box?

Explanation:

The forward force to drag is 125N

Distance of 3m.

The distance is on the positive horizontal 3i+0j

The force is directed upward so that the horizontal and vertical component is

Fx=107N and Fy=65N

F=107i+65j

Work done is dot product of Force and distance

Then,

W=F.ds

W=(107i+65j).(3i+0j)

Note i.i=j.j=1, i.j=j.i=0

Therefore

W=107×3+65×0

W=321J

The workdone done on the box is 321J

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015