Engine emits sound uniformly in all directions, radiating an acoustic power of 3.65 × 10 5 W. 3.65×105 W. Find the intensity of the sound at a distance of 52.7 m 52.7 m from

130.2dB

Explanation:

The formula for determining the intensity of a wave is expressed as

Where P is the power in watts, and A is the area of the sphere formed by the wave

Data given

Power,P=3.65*10^5W

distance,d=52.7

Hence since the distance represent the radius, we can determine the area of the sphere formed

The intensity can be computed as

we can convert to decibel

10.46W/m²

The intensity (I) of a sound is related to the power (P) radiated by the sound within an area (A) as follows;

I =              ----------------(i)

But;

A = 4 r²

Where;

r is the specified distance covered by the sound.

Substitute A = 4 r² into equation (i) to get;

I =               ------------------------(ii)

From the question;

P = acoustic power = 3.65 x 10⁵W

r = 52.7m

To calculate the intensity of the sound, take = 3.142 and substitute other values into equation (ii) as follows;

I =

I =

I = 10.46W/m²

Therefore, the intensity of the sound at that distance is 10.46W/m²

radiation warms things up temp rises convection currents air circ windy weather