You throw a ball of mass 190 g upward. When the ball is 2 m above the ground, headed upward (the initial state), its speed is 18 m/s. Later, when the ball is again 2 m above the ground, this time headed downward (the final state), its speed is 18 m/s. What is the change in the kinetic energy of the ball from initial to final state?

Change in Kinetic energy is zero

Explanation:

Given

Mass of Ball grams Kg

Speed at height of m

Kinetic energy is equal to

Where M is the mass of the object and v is the velocity of the object

Change in kinetic energy

Substituting the given values we get -

Change in kinetic energy

Change in kinetic energy  

Hence, the change in Kinetic energy is zero

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

not too sure thinking all accelerations are pointed down