A 75.0-V and a 45.0-V resistor are connected in parallel. When this combination is connected across a battery, the current delivered by the battery is 0.294 A. When the 45.0-V resistor is disconnected, the current from the battery drops to 0.116 A. Determine (a) the emf and (b) the internal resistance of the battery.

A)   V

B) Ohm

Explanation:

Two resistors are connected in parallel circuit. Thus, the equivalent resistance across the circuit is equal to

Substituting the values of and , we get

Let the internal resistance of the battery be represented by "r"

As per Ohm's law

Where I is the current and R is the resistance

When -V resistor is disconnected, the current from the battery drops to A.

Thus,

   -------- Eq (1)

--------           Eq (2)

Solving equation 1 and 2 , we get

V

Substituting the value of Emf in equation 1, we get -

ohm

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.