Physics, 27.02.2020 02:24 mamas12345

An m = 20.0 g object is held against the free end of a spring of constant k = 25.0 N / m that is compressed a distance x = 10.0 cm from its equilibrium length. Once released, the object slides d 1 = 1.15 m across the tabletop and eventually lands d 2 = 0.2 m from the edge of the table on the floor, as shown in the figure. Calculate the coefficient of friction μ between the table and the object. The sliding distance includes the compression of the spring, and the tabletop is h = 1.00 m above the floor level.

Answers: 3

Show answers

Answers

Answer from: stevegafy

The coefficient of friction μ between the table and the object is 0.546

For us to get the coefficient of friction μ, we will use the law conservation of energy as shown.

According to the law, the elastic energy possessed by the object is equal to the sum of work done and kinetic energy

Mathematically, Elastic energy = work + kinetic energy

$\frac{1}{2} kx^2 = Fd + \frac{1}{2} mv^2$

First, we need to get the initial velocity of the body using the equation of motion as shown:

$\triangle v_x = v_0t + \frac{1}{2} at^2$

Note that the velocity in the y-direction is expressed as:

$\triangle v_y = v_0t + \frac{1}{2} at^2$

Δy = 1.00 m

v₀ = 0 m/s

a = 9.8 m/s²

$1 = 0t + \frac{1}{2}( 9.80t^2)\\1=4.9t^2\\t^2=\frac{1}{4.9} \\t^2=0.2041\\t=0.452secs$

Similarly in the x-direction, recall that

Δx = 0.20 m

a = 0 m/s²

t = 0.452 s

Get the initial velocity v₀ ;

$0.2 = v_0(0.452) + \frac{1}{2} 0(0.452)^2\\0.2=0.452v_0+0v_0=\frac{0.2}{0.452}\\v_0= 0.442m/s$

Next, use conservation of energy to find μ.

Elastic energy = work + kinetic energy

½ kx² = Fd + ½ mv²

½ (25.0) (0.100)² = (0.020× 9.8 × μ) (1.15 m) + ½ (0.020) (0.443 )²

On solving the expression for coefficient of friction, μ = 0.546

Learn more here: link

Answer from: keripressley148

μ = 0.546

Explanation:

First, use kinematics to find the object's velocity at the edge of the table.

Given in the y direction:

Δy = 1.00 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

1.00 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 0.452 s

Given in the x direction:

Δx = 0.20 m

a = 0 m/s²

t = 0.452 s

Find: v₀

Δx = v₀ t + ½ at²

0.20 m = v₀ (0.452 s) + ½ (0 m/s²) (0.452 s)²

v₀ = 0.443 m/s

Next, use conservation of energy to find μ.

Elastic energy = work + kinetic energy

½ kx² = Fd + ½ mv²

½ (25.0 N/m) (0.100 m)² = (0.020 kg × 9.8 m/s² × μ) (1.15 m) + ½ (0.020 kg) (0.443 m/s)²

μ = 0.546

Answer from: Quest

this is a good question! i'll do some research and come back when i have the answer!

Strehe name denean expression ordurina liquid of surface to play tobe ofradius 10m stands upright in

Answer from: Quest

Divide 108.2 x 10^6 into 1.5 x 10 and the result will be in au (astronomical units)

Another question on Physics

Physics, 21.06.2019 20:30

What property is a characteristic of a substance that can be observed and does not change the identity of the substance

Answers: 2

Answer

Physics, 22.06.2019 06:20

Atwo-stage air compressor operates at steady state, compression 10m^3/min of air from 100 kpa and 300k to 1200 kpa. an intercooler between the two stages cools the air to 300k at a constant pressure of 350 kpa. the compression processes are isentropic. a) calculate the power required to run the compressor, in kw b) compare the result to the power required for isentropic compression from the same inlet state to the same final pressure.

Answers: 1

Answer

Physics, 22.06.2019 08:00

Aheat engine running backward is called a refrigerator if its purpose is to extract heat from a cold reservoir. the same engine running backward is called a heat pump if its purpose is to exhaust warm air into the hot reservoir. heat pumps are widely used for home heating. you can think of a heat pump as a refrigerator that is cooling the already cold outdoors and, with its exhaust heat qh, warming the indoors. perhaps this seems a little silly, but consider the following. electricity can be directly used to heat a home by passing an electric current through a heating coil. this is a direct, 100% conversion of work to heat. that is, 19.0 \rm kw of electric power (generated by doing work at the rate 19.0 kj/s at the power plant) produces heat energy inside the home at a rate of 19.0 kj/s. suppose that the neighbor's home has a heat pump with a coefficient of performance of 4.00, a realistic value. note: with a refrigerator, "what you get" is heat removed. but with a heat pump, "what you get" is heat delivered. so the coefficient of performance of a heat pump is k=qh/win. an average price for electricity is about 40 mj per dollar. a furnace or heat pump will run typically 200 hours per month during the winter. what does one month's heating cost in the home with a 16.0 kw electric heater? what does one month's heating cost in the home of a neighbor who uses a heat pump to provide the same amount of heating?

Answers: 2

Answer

Physics, 22.06.2019 11:00

1. jay fills a wagon with sand (about 20 kg) and pulls it with a rope 30 m along the beach. he holds the rope 25° above the horizontal. the rope exerts a 20-n tension force on the wagon. how much work does the rope do on the wagon?

Answers: 1

Answer

You know the right answer?

An m = 20.0 g object is held against the free end of a spring of constant k = 25.0 N / m that is com...

Questions