A projectile is thrown from the top of a building with an initial velocity of 30 m/s in the horizontal direction. If the top of the building is 30 m above the ground, how fast will the projectile be moving just before it strikes the ground

V = 38.582 m/s

Explanation:

Initial Vertical Velocity = 0

Let's use the motion equation given below to solve for the final vertical velocity:

Here a = 9.81 m/s^2

and s = 30 m

Solving for v, we get:

v = 24.261 m/s

This is just the vertical velocity, to get the total velocity we need to add the horizontal component of velocity with this:

Total velocity = Sqrt ( Horizontal Velocity^2 + Vertical Velocity^2)

where  and

V = 38.582 m/s

the independent variable, or the one that is intentionally manipulated is the speed.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.