A charge of uniform linear density 2.00 nC/m is distributed along a long, thin, nonconducting rod. The rod is coaxial with a long conducting cylindrical shell (inner radius = 5.60 cm, outer radius = 9.80 cm). The net charge on the shell is zero. (a) What is the magnitude of the electric field at distance r = 15.4 cm from the axis of the shell? What is the surface charge density on the (b) inner and (c) outer surface of the shell?

(a) E=233.56 N/C

(b) The surface charge density of inner surface  σ= -5.69×10⁻⁹C/m²

(c)The surface charge density of outer surface  σ= 3.25×10⁻⁹C/m²

Explanation:

For Part (a)

The magnitude of the electric field at distance of 15.4 cm from the axis of the shell is given by:

E=λ/2πε₀r

Substitute the given values

Since the nonconducting rod positively charged,it induces a negative charge -q on the inner surface of conducting shell and a positive charge +q on the outer surface of conducting shell,so the net charge of conducting shell is zero

Part (b)

The surface charge density of inner surface is given by:

σ=-q/A

= -λ/2πr

Part(c)

Similarly the surface charge density on the outer surface of the cylindrical shell given by:

σ=λ/2πr

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

it would be kevlar ^^