A 0.25 kg arrow with a velocity of 12 m/s to the west strikes and pierces the center of a 6.8 kg target. What is the final velocity of the combined mass

20/47 meter per second

Explanation:

Mass of arrow(ma)=0.25kg

Velocity of arrow(va)=12m/s

Mass of target(mt)=6.8kg

Velocity of target(vt)=0 since target is at rest

Conservation of linear momentum says that :

maxva+mtxvt=(ma+mt)V

V=(maxva+mtxvt)/(ma+mt)

V=(0.25x12+6.8x0)/(0.25+6.8)

V=3/(7.05)

V=20/47 meter per second

explanation: in any substance/object, the particles inside it (atoms/molecules) constantly move in random directions and with random speeds (this motion is called brownian motion). as a result, the particles have some kinetic energy (which is proportional to the temperature of the substance).

explanation:

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