Four different resistors have various amounts of electric current flowing through them. Given the values of current I and resistance R in each case, order the resistors by the voltage across them, from highest to lowest.

You did not provide the options. However, the options are

I = 6.0, R= 4.0 ohms

I = 9.0, R= 2.0ohms

I = 3.0, R= 2.0ohms

I = 8.0, R= 8.0 ohms

The order of  the resistors from the highest to the lowest is:

I = 8.0, R= 8.0 ohms

I = 6.0, R= 4.0 ohms

I = 9.0, R= 2.0ohms

I = 3.0, R= 2.0 ohms

Explanation:

ohm's law states that voltage across a conductor is directly proportional to the current flowing through it.  V = IR

Based on this formula, the voltages in each of the resistors are calculated below from the highest to the lowest

       V = 8 * 8 =64 volts

      V = 6 * 4 =24 volts

       V = 9 * 2 =18 volts

       V = 3 * 2 =6 volts

a. vertically

explanation:

i tried it and took the test

if im wrong then we have different tests