A gold wire has a 0.30 mm diameter cross section. Opposite ends of this wire are connected to the terminals of a 1.5 V battery. If the length of the wire is 5.5 cm, how much time, on average, is required for electrons leaving the negative terminal of the battery to reach the positive terminal? Assume the resistivity of gold is 2.44 10-8 Ω·m.

Answer :

The time is 0.46 sec.

Explanation:

Given that,

Diameter = 0.30 mm

Voltage = 1.5 V

Length = 5.5 cm

Resistivity of gold

We know that,

The resistance is

...(I)

The current is

...(II)

Put the value of R

We need to calculate the drift velocity

Using formula of drift velocity

Put the value into the formula

We need to calculate the time

Using formula of time

Put the value into the formula

Hence, The time is 0.46 sec.

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation: