A tissue sample at 275 K is submerged in 2 kg of liquid nitrogen at 70 K for cryopreservation. The final temperature of the nitrogen is 75 K. What is the heat capacity of the sample in J/K? (Note: Assume no heat is lost to the surrounding air.) A.0.05 J/K

37.8 J/k

Explanation:

Temperature =T=275 K

Mass of liquid nitrogen=2 kg

Initial temperature=

Final temperature=

We have to find the heat capacity of the sample in J/K.

Specific heat of liquid nitrogen=

We know that

Using the formula

Hence, the heat capacity of sample=37.8 J/k

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

the answer is kevlar