The International Space Station (ISS) flies on a circular orbit with a speed of 7.71 km/s at a height of 330.0 km above the surface of the Earth. What is the centripetal acceleration of the station

Explanation:

Given that

Speed ,v= 7.71 km/s

height ,h = 330 km

We know that ,radius of the earth ,r= 6371 km

R= h + r

R= 330 + 6371 = 6701 km

We know that centripetal acceleration is given as

a=acceleration

v=speed

Now by putting the values in the above equation we get

Therefore the centripetal acceleration will be

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

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