A cubical furnace with external dimensions of 0:6 m is constructed from reclay brick. If the wall thickness is 40 mm, the inner surface temp 630C , and the outer surface temperature is 70C, calculate the heat loss (in kW) from the furnace.

Explanation:

surface area of furnace = 6 x .6²

=2.16 m²

Rate of heat loss = k A ( θ₂ -θ₁ ) / t where k is coefficient of thermal conductivity , A is surface involved , θ₂ -θ₁  is temperature difference and t is thickness .

For fire clay thermal conductivity

= .05 W / m . K

.05 x 2.16 x ( 630 - 70 ) / .04

= 1512 W

= 1.5  kW .

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this