2 masses of 4kg and 2.5kg have a separation of r =1.5m. Calculate the force of gravitational attraction between them (take g as 6.67×10^-^11NM^2kg^-2)

F = 29.64 × 10-¹¹N

Explanation:

From newton's law of gravitation which states that every object in the universe will attract each other with a force which is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

That is,   F = (Gm1m2)/ r²

From the question m1=4kg, m2 = 2.5kg, r= 1.5m,G = 6.67×10-¹¹

F=( 6.67×10-¹¹ × 4 × 2.5) / 1.5²

F = (66.7×10-¹¹) / 2.25

F = 66.7/2.25 × 10-¹¹ N

F = 29.64 × 10-¹¹N

F = 29.64 × 10-¹¹N

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kepler used the data from tycho blahe (his mentor) to construct the laws of planetary motion.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.