A 68 kgkg driver gets into an empty taptap to start the day's work. The springs compress 2.1×10−2 mm . What is the effective spring constant of the spring system in the taptap?

K = 3.1 8 × 10⁴ Nm

Explanation:

Given:

m = 68 Kg

x= 2.1 × 10 ⁻² m (in (2.1×10−2 mm) i think m is repeated just like kgkg in the start of question)

g=9.81 m/s²

K= ?

According to Hooke's Law

F = K x  

also F=mg

⇒ mg = Kx

⇒ K = mg/x

K= 68 Kg × 9.81 m/s² / 2.1 × 10 ⁻² m

K = 3.1 8 × 10⁴ Nm

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!