A block slides down a slope inclined at 37 degrees. If the slope is frictionless and the block starts off at rest, how fast is it moving after it has traveled 1 meter along the plane? Apply energy-conservation principles to solve.

Vf= 3.435 m/s

Explanation:

Given:

Initial velocity Vi =0 m/s (starting from Rest position)

θ = 37⁰

Distance S = 1 m

To find: Final Velocity Vf=?

fist we have to find the down slope net acceleration a = g sin θ

a= 9.81 sin  37⁰ = 5.9 m/s²

By 3rd equation of motion

2 a S= Vf² - Vi²

Vf = Square root ( 2 × 5.9 m/s²  × 1  + 0 m/s)

Vf = Square root (11.8)

Vf= 3.435 m/s

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