Physics, 02.03.2020 20:50 cutie22327

An airplane is flying horizontally with speed 1000km/h(280m/s) when an engine falls off. Neglecting air resistance, assume it takes 30s for the engine to hit the ground. (a) How highis the airplane? (b) How far horizontally does the engine travelwhile it falls? (c) if the airplane somehow continues to fly as ifnothing had happened, where is the engine relative to the airplaneat the moment the engine hits the ground??

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Answer from: popt9710

a) h= 4410 m. b) 8400 m c) just below it.

Explanation:

In the vertical direction, as the engine falls off, its initial velocity is 0. So, we can find the height from which it falls, applying the following kinematic equation for displacement:

$h = \frac{1}{2} * g *t^{2}$

Replacing g = 9.8 m/s², and t = 30 s, we can find h (in m) as follows:

$h = \frac{1}{2} * 9.8 m/s2 * (30s)^{2} = 4410 m$

So, the airplane is at a height of 4410 m when the engine falls off.

Once released, as no other influence acts on the engine in the horizontal direction, it continues moving forward at the same speed that the airplane had at the moment that the engine starts to fall, i.e., 280 m/s.So, the horizontal displacement can be found just applying the definition of average velocity, as follows:

X = v* t = 280 m/s * 30 s = 8400 m

If the airplane keeps flying horizontally at the same speed, it will be always over the engine, as both travel horizontally at the same speed. So, when the engine hits the ground, the airplane will be exactly over it, or the engine exactly below it.

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

Answer from: Quest

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An airplane is flying horizontally with speed 1000km/h(280m/s) when an engine falls off. Neglecting...

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