A paper-filled capacitor is charged to a potential difference of V 0 = 2.5 V V0=2.5 V . The dielectric constant of paper is κ = 3.7 κ=3.7 . The capacitor is then disconnected from the charging circuit and the paper filling is withdrawn, allowing air to fill the gap between the plates. Find the new potential difference V 1 V1 of the capacitor.

Explanation:

We are given that

We have to find the new potential difference of the capacitor.

When the capacitor is disconnected then the charge stored in capacitor is constant.

When we introduce material of dielectric constant k between the plates of capacitor then the capacitance of capacitor increases k times.

Using the formula

Hence, the new potential difference

inverse v=i*r

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