How is lifting a counterweight of a trebuchet considered doing work? Use the definition of work (W = Fd) in your description.

As the counterweight falls through the height h, its gravitational potential energy is  converted to the kinetic energy of the missile; its energy due to its motion, and the gravitational potential energy of the missile; the work done to raise it up from the ground  against the force of gravity.

Explanation:

If we assumed that all of the gravitational potential energy was transferred to kinetic energy  of the missile:

Eg = Ek

m₁g∆h = ½m₂v

Be that as it may, this equation doesn't remain constant since work must be done to lift the shot facing the power of gravity before it is shot into the air. We can accordingly say that the gravitational potential energy of the counterweight when it is suspended, h meters over the ground is equivalent to the expansion of kinetic energy of the missile and the expansion in the gravitational potential energy of the missile:

m₁g∆h = 1/2m₂v

2 + m₂g∆h

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

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