Find the density of seawater at a depth where the pressure is 380 atm if the density at the surface is 1100 kg/m³. Seawater has a bulk modulus of 2.3 × 109 N/m². Bulk modulus is defined to be . Answer in units of kg/m³.

ρ = 1118.13 kg/m^3

Explanation:

Given:

- The expression for Bulk Modulus B is given as:

                                B = ρo * ΔP /Δρ

- Seawater has a bulk modulus of 2.3 × 109 N/m²

Find:

Find the density of seawater at a depth where the pressure is 380 atm if the density at the surface is 1100 kg/m³.

Solution:

- The density at any specified depth can be given as:

                                ρ = ρo + Δρ

- Using the given relation and substitute Δρ:

                                ρ = ρo + ρo * ΔP /B

                                ρ = ρo*( 1 + ΔP /B )

- Plug in the values:

                               ρ = 1100*( 1 + ( 380 - 1 )*10^5 / 2.3*10^9 )

                               ρ = 1118.13 kg/m^3

your answer would be fusion

trig 15.3 cos