A 60 kg child sits on on the outer edge a playground merry-go-around with radius of 4 meters that spins around at 1 revolution every 5 seconds, mercilessly bringing the child ever closer to nausea. What is the child's angular momentum? ( Remember to include the units.) What is the angular momentum of another child with the same mass who is sitting half way out from the center?

a)

b)

Explanation:

a)

The angular momentum of an object in circular motion is given by the formula

where

m is its mass

is its angular velocity

r is the distance of the object from the axis of rotation

For the child in this problem, we have:

m = 60 kg is his mass

r = 4 m is the radius of the merry-go-around

Here the child completes 1 revolution every 5 seconds; so his frequency is

And so his angular speed is

Therefore, the angular momentum is

b)

For a child sitting halfway of the merry-go-around, his distance from the axis of rotation is

The mass of the child is the same as before,

m = 60 kg

And the angular speed is the  same as well: in fact, the merry go around is a rigid body, so all its points cover the same angle in the  same time; so, they all have the same angular speed. Therefore,

Therefore, the angular momentum here is:

i would say the answer is food.

hope this !

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.