Physics, 04.03.2020 01:33 autumng7518

A space station sounds an alert signal at time intervals of 1.00 h . Spaceships A and B pass the station, both moving at 0.400c0 relative to the station but in opposite directions.

Part A
How long is the time interval between signals according to an observer on A?
Part B
How long is the time interval between signals according to an observer on B?
Part C
At what speed must A move relative to the station in order to measure a time interval of 2.00 hbetween signals?

Answers: 2

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Answers

Answer from: fashionblogger28

(A). The the time interval between signals according to an observer on A is 1.09 h.

(B). The time interval between signals according to an observer on B is 1.09 h.

(C). The speed is 0.866c.

Explanation:

Given that,

Time interval = 1.00 h

Speed = 0.400 c

(A). We need to calculate the the time interval between signals according to an observer on A

Using formula of time

$\Delta t=\dfrac{\Delta t_{0}}{\sqrt{1-(\dfrac{v}{c})^2}}$

Put the value into the formula

$\Delta t=\dfrac{1.00}{\sqrt{1-(\dfrac{0.400c}{c})^2}}$

$\Delta t=\dfrac{1.00}{\sqrt{1-(0.400)^2}}$

$\Delta t=1.09\ h$

(B). We need to calculate the time interval between signals according to an observer on B

Using formula of time

$\Delta t=\dfrac{\Delta t_{0}}{\sqrt{1-(\dfrac{v}{c})^2}}$

Put the value into the formula

$\Delta t=\dfrac{1.00}{\sqrt{1-(\dfrac{0.400c}{c})^2}}$

$\Delta t=\dfrac{1.00}{\sqrt{1-(0.400)^2}}$

$\Delta t=1.09\ h$

(C). Here, time interval of 2.00 h between signals.

We need to calculate the speed

Using formula of speed

$\Delta t=\dfrac{\Delta t_{0}}{\sqrt{1-(\dfrac{v}{c})^2}}$

Put the value into the formula

$2.00=\dfrac{1.00}{\sqrt{1-(\dfrac{v}{c})^2}}$

$\sqrt{1-(\dfrac{v}{c})^2}=\dfrac{1.00}{2.00}$

$1-(\dfrac{v}{c})^2=(\dfrac{1.00}{2.00})^2$

$(\dfrac{v}{c})^2=\dfrac{3}{4}$

$v=\dfrac{\sqrt{3}}{2}c$

v=0.866c

Hence, (A). The the time interval between signals according to an observer on A is 1.09 h.

(B). The time interval between signals according to an observer on B is 1.09 h.

(C). The speed is 0.866c.

Answer from: Quest

the grams of oxygen gas that can be produced is 20.6 grams of o₂

calculation

2liclo₃ → 2 licl + 3 o₂

step 1: find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5 +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281 moles

step 2: use the mole ratio to calculate the moles of o2

from equation above, liclo₃: o₂ is 2: 3

therefore the moles of o₂=0.4281 moles x3/2 =0.6422 moles

step 3: find mass of o₂

mass= moles x molar mass

from periodic table the molar mass of o₂ = 16 x2= 32 g/mol

mass=0.6422 moles x 32 g/mol = 20.6 grams of o₂

Answer from: Quest

The modern-day generator works on the principle of electromagnetic induction discovered by michael faraday in 1831-32. faraday discovered that the above flow of electric charges could be induced by moving an electrical conductor, such as a wire that contains electric charges, in a magnetic field.

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A space station sounds an alert signal at time intervals of 1.00 h . Spaceships A and B pass the sta...

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