A spaceship of proper length ? = 100 m travels in the positive x direction at a speed of 0.700 c0 relative to Earth. An identical spaceship travels in the negative x direction along a parallel course at the same speed relative to Earth. At t = 0, an observer on Earth measures a distance d = 58,000 km separating the two ships.

Part A

At what instant does this observer see the leading edges of the two ships pass each other?

The time at which the observer see the leading edges of the two ships pass each other is 0.138 sec.

Explanation:

Given that,

Length = 100 m

Speed = 0.700 c

Distance = 58000 km

The distance should be halved because the spaceships both travel the same speed.

So they will meet at the middle of the distance

We need to calculate the distance

Using formula for distance

Put the value into the formula

We need to calculate the time at which the observer see the leading edges of the two ships pass each other

Using formula of time

Put the value into the formula

Hence, The time at which the observer see the leading edges of the two ships pass each other is 0.138 sec.

answer; /// the above statement is (true);

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .