A conducting sphere of radius R1 carries a charge Q. Another conducting sphere has a radius R2 = 3 4 R1, but carries the same charge. The spheres are far apart. What is the ratio E2 E1 of the electric field near the surface of the sphere with radius R2 to the field near the surface of the sphere with radius R1?

The ratio of electric field is 16:9.

Explanation:

Given that,

Radius

Charge = Q

We know that,

The electric field is directly proportional to the charge and inversely proportional to the square of the distance.

In mathematically term,

Here,

We need to calculate the ratio of electric field

Using formula of electric field

Put the value into the formula

Hence, The ratio of electric field is 16:9.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards