Radioactive waste (krw = 6 W/m-K) is stored in a spherical, stainless steel (kss = 15 W/m-K) container of inner and outer radii equal to ri = 0.5 m and ro = 0.6 m; the inner core of the container is filled to capacity with waste. Heat is generated volumetrically within the waste at a uniform rate of 105 W/m3 , and the outer surface of the container is exposed to a water flow for which h = 825 W/m2 -K and T = 35o C1. Evaluate the steady state outer surface temperature, Ts, o.

2. Evaluate the steady state inner surface temperature, Ts, i .

3. Obtain an expression for the temperature distribution, T(r), in the radioactive wastes. Express your result in terms of ri, Ts, i, krw and q. Evaluate the temperature at r = 0.

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

the only real purpose of sputnik 1 was to beat the us into space. we were getting close to launching a useful satellite, explorer 1 - which launched on january 31, 1958. the ussr had to beat that, so they launched sputnik 1 on october 4, 19