First, test charge +q is brought to point A at a distance r from +Q. Next, +q is removed and a test charge +2q is brought to point B a distance 2r from +Q. Compared with the electric potential energy of the first test charge at A, the electric potential energy of the second test charge at B is

Explanation:

Electric potential is the amount of work needed to move a unit of charge from a reference point to a specific point inside the field.

Then,

Electric potential is given as

U=KQ/r

For test charge q at point A

The test charge is at a distance r from the charge.

Then, electric potential is

U=KQ/r

For test charge q at point B

The test charge is at a distance 2r from the charge.

Then, electric potential is

U=KQ/2r

Electric potential is independent of a test charge, and the magnitude of the charge creating the potential

is the same for both locations, so since B is further from Q than A, the potential there will be less.

and 1and 1