The angles between two forces is 30 degrees. One 220 N force is on the x axis and another is 150 N. Find the direction and magnitude of the resultant of the forces. axis

F = 150.00 N

Explanation:

Let F1 = 220 N, θ1 = 0° ( on the x-axis)

F2 = 150 N and θ2 = 30°

Solution:

For F1

F1x = F1 cos θ = 220 N cos 0° = 220 N

F1y= F1 sin θ = 220 N sin 0° = 0 N

For F2

F2x = F2 cos θ = 150 N cos 30° = 129.904 N

F2y= F2 sin θ = 150 N sin 30° = 75 N

Fx = F1x + F2x = 220 N + 129.904 N

Fx = 349.904 N

Fy = F1y + F2y = 0 N+ 75 N = 75 N

Now resultant vector formula

F = square root ( Fx² + Fy²)

F=  square root ( (129.904 N)² + (75N)²)

F=square root (22500.049)

F = 150.00 N

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