A wire loop of radius 0.37 m lies so that an external magnetic field of magnitude 0.35 T is perpendicular to the loop. The field reverses its direction, and its magnitude changes to 0.19 T in 1.3 s. Find the magnitude of the average induced emf in the loop during this time.

0.053V

Explanation:

Average induced emf is given as:

EMF(avg) = (ΔB * A)/t

Change in magnetic field strength, ΔB= 0.35 - 0.19 = 0.16T

Area, A = 3.142*r² = 3.142 * 0.37²

A = 0.43 m²

EMF(avg) = (0.16 * 0.43) / 1.3

EMF(avg) = 0.053 V

answer: b.

explanation:

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.