The 1.5-kg collar C starts from rest at A and slides with negligible friction on the fixed rod in the vertical plane. Determine the velocity v with which the collar strikes end B when acted upon by the 14.4-N force, which is constant in direction. Neglect the small dimensions of the collar.

Explanation:

check attached image for figure, there is supposed to be a figure for this question containing a distance(height of collar at position A) but i will assume 0.2m or 200mm

Consider the energy equilibrium of the system

Here, F is the force acting on the collar, is the height of the collar at position A, m is the mass of the collar C, g is the acceleration due to gravity, is the velocity of the collar at position B, and is the velocity of the collar at A

Substitute 14.4N for F, 0.2m for , 1.5kg for m, for g and 0 for

Therefore, the velocity at which the collar strikes the end B is 4.412m/s

the force on the thing and the distance the force moves the thing

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