The electric field, generated by a point charge, has strength of 180,000 N/C at a point 1.50 cm from the point charge. What is the charge, if the field points towards the charge

Given Information:  

Electric field = E =  180,000 N/C

Distance = r = 1.50 cm = 0.015 m

Required Information:  

Charge = q = ?

charge = q = 4.5x10⁻⁹ C

Explanation:

The electric field is given by

E = kq/r²

Where k is the coulomb constant k = 9x10⁹ Nm²/C²

q = Er²/k

q = 180,000*(0.015)²/9x10⁹

q = 4.5x10⁻⁹ C

Therefore, the charge is 4.5 nC

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