A series circuit contains two devices one with a resistance of 10 ohms and one with a resistance of 4 ohms the generator supplies a voltage of 42 volt what is the magnitude of the current

Explanation:

When the resistances are connected in series , the total resistance is the sum of individual resistances .

Thus R = R₁ + R₂

here R₁ is resistance of 10 ohms

and R₂ is resistance of 4 ohms .

Thus total resistance R = 10 + 4 = 14 ohm .

The potential difference applied = 42 volt

Thus current I = = =  3 A

Thus current through the circuit is 3 Ampere

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explanation:

i'm only doing this the points

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